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Description

This error occurs when a constant value specified in a partitioned table definition (e.g., in `VALUES LESS THAN` or `VALUES IN`) does not fall within the valid domain or range for its respective partition. It typically arises during `CREATE TABLE` or `ALTER TABLE` operations when defining or modifying partitioned tables, indicating a mismatch between the partition constant and the partitioning function's expected values.

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Error Message

Partition constant is out of partition function domain

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Known Causes

3 known causes

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Constant Exceeds Range Boundary

For `RANGE` partitions, a constant value specified in `VALUES LESS THAN` is not strictly less than the boundary defined for that partition or the preceding partition.

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Constant Missing from List

For `LIST` partitions, a constant value specified in `VALUES IN` does not exist within the discrete list of values defined for that partition.

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Data Type or Expression Mismatch

The data type of the partition constant or the result of a partitioning expression is incompatible with the partitioned column's data type or the partition function's expectations.

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Solutions

3 solutions available

1. Verify Partition Function Domain and Constant Values medium

Ensure the constants used in your partition definition fall within the domain defined by your partition function.

1

Examine the `CREATE TABLE` statement or `ALTER TABLE` statement that defines your partitions. Identify the `PARTITION BY` clause and the specific partition function being used (e.g., `RANGE`, `LIST`, `HASH`).

SHOW CREATE TABLE your_table_name;

2

Carefully review the `VALUES LESS THAN` (for `RANGE` partitioning) or `VALUES IN` (for `LIST` partitioning) clauses for each partition. Compare these values against the expected domain of your partition function.

-- Example for RANGE partitioning:
-- Partition 1: PARTITION p0 VALUES LESS THAN (100)
-- Partition 2: PARTITION p1 VALUES LESS THAN (200)
-- If you try to insert a value >= 200, you'll get this error.

-- Example for LIST partitioning:
-- Partition 1: PARTITION p_usa VALUES IN ('USA')
-- Partition 2: PARTITION p_canada VALUES IN ('CANADA')
-- If you try to insert a value other than 'USA' or 'CANADA', you'll get this error.

3

If the constant is indeed outside the defined domain, you have two primary options: either adjust the constant value to fall within the domain or redefine the partition function to accommodate the desired values. The latter usually involves altering the table structure.

ALTER TABLE your_table_name ADD PARTITION (PARTITION new_partition_name VALUES LESS THAN (new_value)); -- For RANGE
ALTER TABLE your_table_name ADD PARTITION (PARTITION new_partition_name VALUES IN (new_value)); -- For LIST

2. Redefine Partitioning Strategy for New Values advanced

Modify the table's partitioning to include a partition that can handle the new constant value.

1

Identify the exact value that is causing the error. This is usually evident from the error message or by observing the data being inserted.

SELECT * FROM your_table_name WHERE your_partition_column = 'problematic_value';

2

Determine where this new value *should* logically fit within your partitioning scheme. For `RANGE` partitioning, this means finding the correct `VALUES LESS THAN` boundary. For `LIST` partitioning, this means adding a new `VALUES IN` set.

--- For RANGE: If your partitions are at 100, 200, 300 and you get an error for 250, you might need to add a partition for 250 or adjust existing ones.
--- For LIST: If you have partitions for 'A', 'B' and get an error for 'C', you need to add a partition for 'C'.

3

Use `ALTER TABLE` to add a new partition that encompasses the problematic value or to redefine existing partitions. Be cautious when redefining partitions, as it can be a resource-intensive operation and might require downtime.

-- Example: Adding a new partition for RANGE partitioning
ALTER TABLE your_table_name ADD PARTITION (PARTITION p_new_range VALUES LESS THAN (350)); -- Assuming 350 is the next logical boundary

-- Example: Adding a new partition for LIST partitioning
ALTER TABLE your_table_name ADD PARTITION (PARTITION p_new_list VALUES IN ('C'));

4

If you are dealing with `HASH` or `KEY` partitioning, this error is less common but can occur if the partition function's internal logic is somehow misaligned with the number of partitions. In such rare cases, you might need to re-create the table with a different number of partitions or a different partitioning strategy.

ALTER TABLE your_table_name PARTITION BY HASH(your_column) PARTITIONS 16; -- Example of re-partitioning

3. Re-evaluate Partitioning Strategy for Dynamic Data advanced

If your data distribution changes frequently, consider a more flexible partitioning strategy or a different approach.

1

Analyze the nature of the data that is causing the 'Invalid Partition Constant Domain' error. Is it a predictable pattern, or is it truly random and unpredictable?

SELECT DATE(your_partition_column), COUNT(*) FROM your_table_name GROUP BY DATE(your_partition_column) ORDER BY DATE(your_partition_column) DESC LIMIT 100;

2

If you're using `RANGE` partitioning based on dates and new date ranges are constantly appearing, consider using `PARTITION BY RANGE COLUMNS` which is more flexible for non-contiguous ranges, or consider a different partitioning scheme altogether.

-- Example of RANGE COLUMNS partitioning:
CREATE TABLE your_table_name (
    id INT,
    event_date DATE
)
PARTITION BY RANGE COLUMNS (event_date) (
    PARTITION p0 VALUES LESS THAN ('2023-01-01'),
    PARTITION p1 VALUES LESS THAN ('2023-02-01'),
    PARTITION p2 VALUES LESS THAN ('2023-03-01')
);

3

For very dynamic data, especially if it's time-series based, consider partitioning by month or year and then using automated scripts to add new partitions regularly. This proactive approach can prevent this error.

-- Example of a bash script to add monthly partitions (simplified):

#!/bin/bash

TABLE_NAME="your_table_name"
CURRENT_MONTH=$(date +"%Y-%m")
NEXT_MONTH=$(date -d "$(date +%Y-%m-01) +1 month" +"%Y-%m")

PARTITION_EXISTS=$(mysql -u root -pPASSWORD -e "USE your_database; SHOW CREATE TABLE ${TABLE_NAME};" | grep "PARTITION p${NEXT_MONTH}")

if [ -z "$PARTITION_EXISTS" ]; then
    echo "Adding partition for ${NEXT_MONTH}"
    mysql -u root -pPASSWORD -e "USE your_database; ALTER TABLE ${TABLE_NAME} ADD PARTITION (PARTITION p${NEXT_MONTH} VALUES LESS THAN ('${NEXT_MONTH}-01'));"
else
    echo "Partition for ${NEXT_MONTH} already exists."
fi

4

If the error is consistently occurring with `LIST` partitioning and a wide variety of values, it might indicate that `LIST` partitioning is not the most suitable strategy. Consider switching to `RANGE` partitioning if there's an inherent order to the values, or if the data is truly unstructured, you might need to reconsider partitioning altogether for that specific column.

ALTER TABLE your_table_name PARTITION BY RANGE (your_column); -- If applicable

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Related Errors

5 related errors

MariaDB Error 1563: Invalid Partition Constant Domain